Taysom Hill winning NFC Offensive Player of the Week is a no-brainer

The New Orleans Saints scored 39 points to get the win over the Seattle Seahawks on Sunday. Offensive weapon Taysom Hill scored 28 of those 39 points. He did so by running for three touchdowns and tossing for one as well. The dude was on fire.

As a result, it should come as no surprise that Hill is this week's recipient of NFC Offensive Player of the Week for his efforts against the Seahawks.

Taysom Hill was the easy choice for NFC Offensive Player of the Week

"Hill set career highs with 112 rushing yards and three rushing touchdowns and added a 22-yard touchdown pass in the Saints’ 39-32 win over Seattle. He became the third player ever to record at least 100 rushing yards, three rushing touchdowns and a touchdown pass in a single game, joining Ronnie Brown (September 21, 2008) and Pro Football Hall of Famer LaDainian Tomlinson (September 25, 2005). This marks the first career Offensive Player of the Week award for Hill and his second-career Player of the Week award overall, having previously been named Special Teams Player of the Week in Week 14, 2018. Hill becomes the second New Orleans tight end to win the award, joining Jimmy Graham (Week 10, 2012 and Week 3, 2013). "

- NFL Communications

As mentioned in the blurb above, this is the first time that Hill has won this title as an offensive player but he had won it on special teams before in 2018. It's also still funny to me to see Hill listed as a tight end when he's really just an all-around weapon. That's why people refer to him as the Saints' swiss army knife. The guy does it all.

The Saints are a better football team when Taysom Hill is on the field and lining up in a variety of roles. Defenses have no clue on how to stop Hill and that's why he's such a dangerous threat.

Well-earned on the award and hopefully this is the first of more to come!